If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
a^3*((4*a^5*b^2)/12)*b = 0
1/3*a^8*b^3 = 0
x naleu017Cy do R
x in (-oo:+oo)
| x=2x+x-3 | | 72=9h | | -10x^2+6x+448=0 | | 18y=24y^2 | | x-1/3=-5 | | -27=35d+8 | | 5+4a=13 | | (9b-4)-4(2b+2)=-3 | | 9x+3=12x-3 | | Y/6=34 | | x/3-10=-2 | | 10x+3=-3x+12-4x | | 5t=6.5 | | 5u=100 | | 7x+4x+3+8=8x+3+2x | | x/6=x/8+5 | | 2x^2+6=168 | | 2n-13=46 | | 7x+4x+3+8=8x+3+2 | | 3n+15+7=26 | | x/2+1=19 | | -4y+2=-5y+1 | | abs(6x-3)=9 | | 1x+2y=11 | | 9t-21=3(t-7)+6 | | 3z-6=9 | | 1/3t-8 | | 3a+7=5a+4 | | 450x=1320-250x | | 8=y+13 | | 3b+15=8b-5 | | 9m+10-14n=-5 |